Welcome Guest. Sign in or Signup

2 Answers

How can we roughly determine the wind component, without crosswind component chart?

Asked by: 4372 views Aerodynamics, General Aviation

Ace Any FAA Written Test!
Actual FAA Questions / Free Lifetime Updates
The best explanations in the business
Fast, efficient study.
Pass Your Checkride With Confidence!
FAA Practical Test prep that reflects actual checkrides.
Any checkride: Airplane, Helicopter, Glider, etc.
Written and maintained by actual pilot examiners and master CFIs.
The World's Most Trusted eLogbook
Be Organized, Current, Professional, and Safe.
Highly customizable - for student pilots through pros.
Free Transition Service for users of other eLogs.
Our sincere thanks to pilots such as yourself who support AskACFI while helping themselves by using the awesome PC, Mac, iPhone/iPad, and Android aviation apps of our sponsors.

2 Answers

  1. Best Answer

    Mark Kolber on Jan 27, 2014

    There’s a common rule of thumb for a rough calculation.

    1. The 45 degree multiplier is 0.7 for headwind, tailwind & crosswind components.
    2. For every 15 degree variation in wind direction from the 45 degree position, the 0.7 multiplier is adjusted by 0.2

    So, for example, It’s runway 9 and wind is 150 degrees at 14kts. That’s a 60° wind (150-90=60) The crosswind multiplier is .9 (.7+.2), So your Crosswind Component is 13 kts (14*0.9)

    Now, even that is too much math in the cockpit, for me anyway. And winds of any magnitude tend on to be constant. So, it can be simplified a lot for the real world.
    • 30° off the nose is a 50% crosswind component.
    • about 45° off the nose, about 75% of it is crosswind component
    • Any more than that, it’s all crosswind

    That’s of course a rough number, but since it’s only a guide to how much work you’ll probably have to do or whether to go elsewhere, it’ more than enough for many.

    +6 Votes Thumb up 6 Votes Thumb down 0 Votes

  2. rizwan on Feb 13, 2014

    I follow the same rule but a little different way… it is 9’5 rule..if wind is 11 o clock.. head wind is 90 percent and cross wind half(50 percent). if wind is 10 o clock cross wind is 90 percent and head wind 50 percent(half) …45 degree either side 70 percent is head wind and cross wind

    wind 20 kts 11 o clock HW 20 x 0.9 = 18kts , CW 20 x 0.5 =10 kts
    wind 20 kts 10 o clock HW 20 x 0.5 =10 kts CW 20x 0.9 = 18 kts
    wind 20 kts 45 degree off …. HW 20x 0.7 =14 kts CW 20 x 0.7 =14 kts

    0 Votes Thumb up 0 Votes Thumb down 0 Votes

The following terms have been auto-detected the question above and any answers or discussion provided. Click on a term to see its definition from the Dauntless Aviation JargonBuster Glossary.

Answer Question

Our sincere thanks to all who contribute constructively to this forum in answering flight training questions. If you are a flight instructor or represent a flight school / FBO offering flight instruction, you are welcome to include links to your site and related contact information as it pertains to offering local flight instruction in a specific geographic area. Additionally, direct links to FAA and related official government sources of information are welcome. However we thank you for your understanding that links to other sites or text that may be construed as explicit or implicit advertising of other business, sites, or goods/services are not permitted even if such links nominally are relevant to the question asked.